Exams › NEET › Chemistry

Given initial volume (V₁) = 500 mL; Initial temperature (T₁) = 27°C = 300 K and final temperature (T₂) = -5°C = 268 K. From Charles's law, calculate V₂.

1. 500/300 × 268
2. 446.66 mL
3. 500 × 268/300
4. New volume of gas

Correct answer: 446.66 mL

Solution

Using Charles's law, V₁/T₁ = V₂/T₂. Substituting the values: 500/300 = V₂/268, solving gives V₂ = 446.66 mL.

Related NEET Chemistry questions

• Which of the following is a true solution?
• State in which of the following examples the force of attraction between particles of matter is almost negligible.
• Dry ice is:
• Which of the following statement about Avogadro's hypothesis is correct?
• Vapour pressure of a liquid increases with :
• Who proposed that equal volumes of gases at the same temperature and pressure have same number of molecules.

⚔️ Practice NEET Chemistry free + battle 1v1 →