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The pressure exerted by 6.0 g of methane gas in a 0.03 m³ vessel at 129°C is (Atomic masses: C = 12.01, H = 1.01 and R = 8.314 J K⁻¹ mol⁻¹):

1. 31684 Pa
2. 215216 Pa
3. 13409 Pa
4. 41648 Pa

Correct answer: 41648 Pa

Solution

First, calculate the moles of methane (CH₄) using its molar mass (16.04 g/mol). Then, use the ideal gas equation, PV = nRT, with T in Kelvin (129°C = 402 K) and solve for pressure (P). The result is 41648 Pa.

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