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What is the density of N2 gas at 227°C and 5.00 atm pressure? (R = 0.0821 atm K^-1 mol^-1)

1. 0.29 g/ml
2. 1.40 g/ml
3. 2.81 g/ml
4. 3.41 g/ml

Correct answer: 2.81 g/ml

Solution

To calculate the density of N2 gas, we use the ideal gas law in the form: density (d) = (PM) / (RT). Here, P = 5.00 atm, M (molar mass of N2) = 28 g/mol, R = 0.0821 atm·L·mol^-1·K^-1, and T = 227°C = 500 K. Substituting, d = (5.00 × 28) / (0.0821 × 500) = 2.81 g/L = 0.00281 g/ml. Thus, the correct answer is C.

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