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A woman with two genes for haemophilia and a gene for colour blindness on one of the 'X' chromosomes marries a normal man. How will the progeny be?

1. haemophilic and colour-blind daughters
2. 50% haemophilic colour-blind sons and 50% haemophilic sons
3. 50% haemophilic daughters and 50% colour-blind daughters
4. All sons and daughters haemophilic and colour-blind

Correct answer: 50% haemophilic colour-blind sons and 50% haemophilic sons

Solution

A normal father gives a Y to sons, so all sons depend on the mother's X chromosome. Since one maternal X carries both haemophilia and colour blindness while the other carries only haemophilia, the sons split into two equal groups: one with both traits and one with haemophilia only.

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