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A diseased man marries a normal woman. They have three daughters and five sons. All the daughters were diseased and sons were normal. The gene of this disease is

1. sex-linked dominant
2. sex-linked recessive
3. sex-linked character
4. autosomal dominant

Correct answer: sex-linked dominant

Solution

An affected father gives his X chromosome to all daughters and his Y chromosome to all sons. If the disease is on the X chromosome and dominant, every daughter inherits the affected X and is diseased, while sons receive the father's Y and remain normal if the mother is unaffected. This matches the pattern exactly.

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