In a genetic cross having recessive epistasis, F2 phenotypic ratio would be
9 : 6 : 1
15 : 1
9 : 3 : 4
12 : 3 : 1
Correct answer: 9 : 3 : 4
Solution
In recessive epistasis, the homozygous recessive condition at one locus masks expression of the other locus, so one phenotypic class combines two genotypes. This changes the standard dihybrid ratio to 9:3:4.