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How many different types of genetically different gametes will be produced by a heterozygous plant having the genotype: AABbCc?

1. Two
2. Four
3. Six
4. Nine

Correct answer: Four

Solution

The genotype AABbCc has two heterozygous loci: Bb and Cc. Each heterozygous pair contributes 2 possible alleles to gametes, so the total number of genetically different gametes is 2^2 = 4.

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