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In a dihybrid cross AABB x aabb, F2 progeny of AABB, AABb, AaBB and AaBb occurs in the ratio of

1. 1 : 1 : 1 : 1
2. 9 : 3 : 3 : 1
3. 1 : 2 : 2 : 1
4. 1 : 2 : 2 : 4

Correct answer: 1 : 2 : 2 : 4

Solution

The F1 from AABB × aabb is all AaBb, and selfing AaBb gives independent segregation at A and B. The genotype frequencies for A and B are 1:2:1 each, so combining them gives AABB : AABb : AaBB : AaBb = 1 : 2 : 2 : 4.

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