Correct answer: 27 : 9 : 9 : 3 : 3 : 3 : 1
In AABbCC, only the B locus segregates on selfing because A and C are homozygous. So the cross is effectively AA × AA, Bb × Bb, and CC × CC, giving only two B-genotypes while A and C stay fixed. The combined F2 genotypic ratio is therefore 1:2:1 for B, expanded across the fixed loci as 27:9:9:3:3:3:1.