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A male human is heterozygous for autosomal genes A and B and is also hemizygous for hemophilic gene h. What proportion of his sperms will be abh?

1. 1/8
2. 1/32
3. 1/16
4. 1/4

Correct answer: 1/8

Solution

For A and B, a heterozygous male produces half his sperm with a and half with b at each locus, so the chance of getting both recessive autosomal alleles is 1/2 × 1/2. Because he is hemizygous for h, every sperm carries h, so the total is 1/4 × 1 = 1/4? Wait—since the target is specifically abh, the autosomal part is a and b together from two separate heterozygous loci, giving 1/2 × 1/2 = 1/4, and with h always present the final fraction is 1/4.

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