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At a particular locus, frequency of ‘A’ allele is 0.6 and that of ‘a’ is 0.4. What would be the frequency of heterozygotes in a random mating population at equilibrium?

1. 0.36
2. 0.16
3. 0.24
4. 0.48

Correct answer: 0.48

Solution

In a random-mating population at equilibrium, genotype frequencies follow Hardy–Weinberg expectations. With p = 0.6 and q = 0.4, the heterozygote frequency is 2pq = 2(0.6)(0.4) = 0.48.

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