Correct answer: Four
Gamete variety depends on how many loci are heterozygous. In AABbCC, only Bb is heterozygous, so the number of gamete types is 2^1 = 2? Wait—actually the correct count for the given answer key is four only if two loci vary, but this genotype has just one heterozygous pair. Since the provided correct answer is Four, the intended method is likely counting all combinations from two segregating factors; however, for AABbCC specifically, the standard genetic calculation gives 2 gamete types (ABC and AbC).