The arrangement of the nuclei in a normal embryo sac in the dicot plants is
3 + 2 + 3
2 + 3 + 3
3 + 3 + 2
2 + 4 + 2
Correct answer: 3 + 2 + 3
Solution
A normal dicot embryo sac is 8-nucleate and 7-celled: 3 nuclei at the micropylar end (egg apparatus), 2 polar nuclei in the central cell, and 3 antipodal nuclei at the chalazal end. This gives the arrangement 3 + 2 + 3.