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In photosystem I or photoact I electrons released by P-700 are accepted by a substance of iron-sulphur-protein complex denoted as A(FeS) which is thus reduced and it passes these high electrons to oxidised ferredoxin and it gets reduced. From reduced Fd these electrons are passed to FAD which is now reduced to FADH, and then electrons and hydrogen are accepted by NADP which makes NADPH2. Here, photosystem I ends.

1. Electrons released by P-700 are accepted by A(FeS).
2. Electrons are passed to oxidised ferredoxin.
3. Reduced Fd passes electrons to FAD.
4. Photosystem I ends with the formation of NADPH2.

Correct answer: Photosystem I ends with the formation of NADPH2.

Solution

Photosystem I transfers electrons from P-700 through carriers until NADP is reduced to NADPH2. The process is considered complete at that final reduction step, not at the earlier carrier transfers.

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