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Fixation of one CO2 molecule through Calvin cycle requires

1. 1 ATP and 2NADPH2
2. 2ATP and 2NADPH2
3. 3ATP and 2NADPH2
4. 2ATP and 1NADPH2

Correct answer: 2ATP and 2NADPH2

Solution

In the Calvin cycle, fixing one CO2 ultimately requires reduction of the resulting 3-carbon intermediate and regeneration of the CO2 acceptor. That costs 2 ATP and 2 NADPH2 per CO2 fixed.

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