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Normal woman whose father was colour blind would have received the X chromosome from her father (XcY) → Parents : (P1) : (♀) XcX × XcY (♂) Progeny (F1) : XcXc XcX XcY XY colour normal colour normal blind daughter blind son daughter son

1. (a) XcXc
2. (b) XcX
3. (c) XcY
4. (d) XY

Correct answer: (a) XcXc

Solution

The mother is a carrier of the colour blindness gene, so she has one normal X chromosome and one X chromosome with the colour blindness gene. She can pass either X chromosome to her daughter, so the daughter has a 50% chance of inheriting the colour blindness gene and being colour blind.

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