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ExamsJEE MainPhysics

A binary star system consists of star A (mass 2.2 Ms) and star B (mass 11 Ms), where Ms is the solar mass. They are separated by distance d and revolve about their common, stationary centre of mass. Find the ratio of the total angular momentum of the binary system to the angular momentum of star B alone, both about the centre of mass.

  1. 6
  2. 5
  3. 1.2
  4. 3

Correct answer: 6

Solution

Let mA = 2.2Ms, mB = 11Ms (ratio mB/mA = 5). Distances from COM: rA = d*mB/(mA+mB), rB = d*mA/(mA+mB). Angular momentum L = m r² omega. LA/LB = (mA rA²)/(mB rB²) = (mA/mB)*(rA/rB)² = (mA/mB)*(mB/mA)² = mB/mA = 5. So L_total/L_B = (LA + LB)/LB = LA/LB + 1 = 5 + 1 = 6.

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