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A satellite in a circular orbit of radius R has period T. What is the period of another satellite orbiting the same body in a circular orbit of radius 4R?
- 4T
- T/8
- T/4
- 8T
Correct answer: 8T
Solution
By Kepler's third law T² ~ r³, so T ~ r^(3/2). For r increased to 4R: T2 = T*(4)^(3/2) = T*8 = 8T.
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