A person standing in a lift holds a jar of water that has a small hole in the lower part of its side wall. When the lift is at rest, the emerging water jet strikes the lift floor at a horizontal distance d = 1.2 m from the person. Match the lift's state of motion (List I) with the horizont

Question

A person standing in a lift holds a jar of water that has a small hole in the lower part of its side wall. When the lift is at rest, the emerging water jet strikes the lift floor at a horizontal distance d = 1.2 m from the person. Match the lift's state of motion (List I) with the horizontal distance the jet travels (List II). List I: (P) Lift accelerating upward; (Q) Lift accelerating downward with acceleration less than g; (R) Lift moving up at constant speed; (S) Lift in free fall. List II: (1) d = 1.2 m; (2) d > 1.2 m; (3) d < 1.2 m; (4) No water leaks out.

Accepted Answer

P-2, Q-3, R-1, S-4. Efflux speed v = sqrt(2*g_eff*h). When the lift accelerates up, g_eff > g, so the jet is faster and lands farther (d > 1.2). When accelerating down (a < g), g_eff < g, jet slower, lands nearer (d < 1.2). Constant velocity keeps g_eff = g (d = 1.2). In free fall g_eff = 0, pressure vanishes and no water comes out.

Solution

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