Correct answer: 48.83 N
At the pole there is no rotational effect, so W_pole = m*g = 49 N, giving m = 5 kg. At the equator the centripetal term reduces the reading: W_eq = m*(g - omega²*R). omega = 2*pi/(86400 s) = 7.27*10⁻⁵ rad/s. omega²*R = (7.27e-5)² * 6.4e6 = 5.29e-9 * 6.4e6 = 0.0338 m/s². So W_eq = 5*(9.8 - 0.0338) = 5*9.766 = 48.83 N.