The shearing stress between adjacent horizontal layers of water in a river is 1.5 milli-newton per square metre. If the coefficient of viscosity of water is eta = 1*10⁻³ Pa*s, the velocity gradient (in s⁻¹) is:

Question

Accepted Answer

1.5. Newton's law of viscosity gives shear stress = eta*(dv/dx). So dv/dx = stress/eta = (1.5*10⁻³ N/m²)/(1*10⁻³ Pa*s) = 1.5 s⁻¹.

The shearing stress between adjacent horizontal layers of water in a river is 1.5 milli-newton per square metre. If the coefficient of viscosity of water is eta = 110⁻³ Pas, the velocity gradient (in s⁻¹) is:

Solution

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