Exams › JEE Main › Physics
A thin uniform annular disc of mass M has outer radius 4R and inner radius 3R. Find the work needed to move a unit mass from a point P on its axis, located at distance 4R from the centre, to infinity.
- (2GM/(7R)) * (4*sqrt(2) - 5)
- (GM/(4R))
- (2GM/(5R)) * (sqrt(2) - 1)
- (GM/(7R)) * (4*sqrt(2) - 5)
Correct answer: (2GM/(7R)) * (4*sqrt(2) - 5)
Solution
The axial potential of the annulus is found by integrating ring contributions from inner to outer radius; the required work is the magnitude of this potential at P (point at distance 4R on the axis).
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →