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A tall cylindrical container is half filled with liquid and spun about its vertical axis. The liquid climbs up the walls. If the container radius is 5 cm and it spins at 2 revolutions per second, what is the height difference (in cm) between the liquid at the centre and at the wall?
- 1.2
- 0.1
- 2.0
- 0.4
Correct answer: 2.0
Solution
The difference in height between the wall and the axis of a rotating liquid equals omega²*R²/(2g).
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