Exams › JEE Main › Physics
A neutral spherical metallic conductor has a spherical cavity. A positive point charge sits at the centre of the cavity, and another positive point charge is placed outside the conductor. Match each cause in Column-I with the effects it produces in Column-II. Column-I (Cause): (A) The outside charge is moved to a new position. (B) The inside (cavity) charge is moved to a new position within the cavity. (C) The magnitude of the charge inside the cavity is increased. (D) The conductor is earthed. Column-II (Effect): (P) The charge distribution on the inner surface of the cavity changes. (Q) The charge distribution on the outer surface of the conductor changes. (R) The electric potential at the centre due to the charges on the outer surface changes. (S) The force on the charge inside the cavity changes. Which single option lists effects that genuinely occur for the matched causes overall?
- (P), (Q), (R) and (S)
- (P), (Q) and (S) only
- (Q), (R) and (S) only
- (P), (R) and (S) only
Correct answer: (P), (Q), (R) and (S)
Solution
Electrostatic shielding decouples inside and outside. (A) Moving the outside charge changes outer-surface distribution (Q) and the potential at the centre from outer charges (R); it does not change the inner cavity field or the force on the inside charge. (B) Moving the inside charge changes the inner-surface induced distribution (P) and the force on the inside charge (S). (C) Increasing the inside charge changes inner-surface (P), outer-surface (Q) and potentials (R). (D) Earthing changes the outer surface charge (Q) and potential (R). Across all causes, every effect (P), (Q), (R) and (S) is produced, so the inclusive option is correct.
Related JEE Main Physics questions
- Two identical conducting spheres A and B, each of radius R, carry equal charges and are separated by a large distance d (d >> R), exerting a force f0 on each other. A neutral conducting sphere of radius 2R is first touched to sphere A, then touched to sphere B, and finally removed far away. What is the new electrostatic force between A and B?
- A small sphere of mass 80 g carrying charge q is held 9 m vertically above the centre of a fixed non-conducting sphere of radius 1 m that also carries charge q. When released, the small sphere falls freely until it is repelled and just barely stops before touching the fixed sphere. Given g = 9.8 m/s², the charge q equals 7K micro-coulombs. Find K.
- A uniformly charged non-conducting solid sphere of radius R carries total charge Q. A narrow tunnel is drilled through the sphere along a diameter. A point charge q of mass m is placed at one end of the tunnel (on the surface of the sphere, point A) and released. What is the minimum initial speed v0 that must be given to the charge so that it reaches the other end B (diametrically opposite point on the surface)?
- A total nuclear charge Ze is distributed non-uniformly inside a nucleus of radius R, with a radial charge density rho(r) that varies linearly with r (rho(r) = a + b*r for r <= R, fixed so that the total enclosed charge is Ze). Which statement is correct?
- A uniform electric field of magnitude E lies in the x-y plane, making angle theta with the x-axis (as in the figure). Find the potential difference V(O) - V(A) between the origin O and the point A(d, d, 0).
- Two identical charged spheres hang from a common point on two massless threads of length l and, because of mutual repulsion, settle a small distance x = d apart (d << l). Charge now leaks off both spheres at a constant rate, and the spheres approach each other with speed v. How does v depend on the separation x?
⚔️ Practice JEE Main Physics free + battle 1v1 →