Steam at 100 degC is passed into 1.1 kg of water at 15 degC kept in a calorimeter whose water equivalent is 0.02 kg, until the mixture reaches 80 degC. Find the mass of steam that condenses (in kg). Take latent heat of steam = 540 cal/g and specific heat of water = 1 cal/g/degC.

Question

Accepted Answer

0.130. Balancing heat: m*(540 + 20) = 1120*(80 - 15), giving m about 130 g = 0.130 kg.

Steam at 100 degC is passed into 1.1 kg of water at 15 degC kept in a calorimeter whose water equivalent is 0.02 kg, until the mixture reaches 80 degC. Find the mass of steam that condenses (in kg). Take latent heat of steam = 540 cal/g and specific heat of water = 1 cal/g/degC.

Solution

Related JEE Main Physics questions