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How much heat must be supplied to an ice-water mixture to change its total volume by 1 cm³? (Density of ice = 0.9 times density of water; latent heat of fusion of ice L = 80 cal/g.)

1. 360 cal
2. 500 cal
3. 720 cal
4. none of these

Correct answer: 720 cal

Solution

To change volume by 1 cm³, 9 g of ice must melt, requiring 9 * 80 = 720 cal.

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