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The rate of emission of radiation by a black body at 273 deg C is E. What is its rate of emission of radiation at 0 deg C?
- E/16
- E/4
- E/8
- 0
Correct answer: E/16
Solution
Since rate is proportional to T⁴ and the absolute temperatures are in ratio 546:273 = 2:1, the rate falls by (1/2)⁴ = 1/16, giving E/16.
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