Exams › JEE Main › Physics
A steel ball at an initial pressure of 1.0e5 Pa is heated from 20°C to 120°C while its volume is held constant. Find the pressure inside the ball. Linear expansion coefficient of steel = 12e-6 /°C; bulk modulus of steel = 1.6e11 N/m².
- 1.0e5 Pa
- 2.0e8 Pa
- 1.9e8 Pa
- 1.6e8 Pa
Correct answer: 1.9e8 Pa
Solution
Holding volume constant requires a compressive pressure K*3*alpha*ΔT ≈ 1.9e8 Pa, which dominates the initial pressure, giving about 1.9e8 Pa.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →