Exams › JEE Main › Physics

Steam keeps the inner surface of a 50 cm long rubber tube at 120°C; the tube has inner radius 1.0 cm and outer radius 1.2 cm. The room is at 30°C. Taking the thermal conductivity of rubber as 0.15 J/m-s-°C, find the rate of radial heat conduction through the tube wall.

1. 183 J/s
2. 207 J/s
3. 233 J/s
4. 280 J/s

Correct answer: 233 J/s

Solution

Using the cylindrical-shell conduction formula with ln(1.2) ≈ 0.182 gives about 233 J/s.

Related JEE Main Physics questions

• A cube initially at 0°C is subjected to the same external pressure P on all its faces, causing it to be compressed. How much must its temperature be increased so that the cube regains its original size? The bulk modulus of the cube material is B and its coefficient of linear expansion is α.
• If λm represents the wavelength at which a black body emits radiation most strongly at temperature T K, then which relation is true?
• Which of the following statements about heat transfer is/are incorrect?
• A composite wall consists of two slabs, A and B, of equal thickness but made of different materials. Their thermal conductivities satisfy K_A = 3K_B. If the total temperature difference across the wall is 20°C, then in steady thermal equilibrium:
• An evacuated bulb contains a filament that is 10 cm long and 0.2 mm in diameter. If its emissivity is 0.2, determine the radiant power emitted by the filament at 2000 K. Take σ = 5.67 × 10⁻⁸ W/m² K⁴.
• A rectangular solid is raised in temperature from 0°C to 100°C. If its length increases by 0.10% over this interval, what is the corresponding percentage increase in its volume?

⚔️ Practice JEE Main Physics free + battle 1v1 →