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A thermally insulated vessel holds 100 g of water at 0 degC. The air above is pumped out, so some water freezes while some evaporates, all at 0 degC, until no liquid water remains. Find the mass of ice formed. Latent heat of vaporization at 0 degC = 2.10 * 10⁶ J/kg; latent heat of fusion of ice = 3.36 * 10⁵ J/kg.
- 40 g
- 78 g
- 86 g
- 94 g
Correct answer: 86 g
Solution
Energy balance m*Lv = (100 - m)*Lf gives m ≈ 13.8 g evaporated, so ice formed ≈ 86 g.
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