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Several identical rods, each of thermal conductance K and cross-sectional area A, form a symmetric network in which the rods AB, AO and AD branch out from corner A and recombine toward corner C. The ends A and C are held at temperatures 2*T0 and T0 respectively. By the symmetry of the network, which of the following statements is correct?
- The rate of heat flow through AB, AO and AD is the same
- The rate of heat flow through BO and OD is different
- The temperature at junction B differs from that at junction D
- No heat flows from A to C
Correct answer: The rate of heat flow through AB, AO and AD is the same
Solution
Because the three branches from A are symmetric and identical, they each carry an equal share of the total heat current, and the symmetric junctions reach the same temperature. Thus the equal-flow statement is correct, while the statements claiming asymmetry are false, and heat clearly flows since 2*T0 > T0.
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