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A thermally insulated vessel holds 150 g of water at 0 C. Air is pumped out adiabatically, so part of the water freezes while the rest evaporates, all at 0 C. Estimate the mass of water that evaporates. (Latent heat of vaporization = 2.10 x 10⁶ J/kg, Latent heat of fusion = 3.36 x 10⁵ J/kg)
- 130 g
- 35 g
- 20 g
- 150 g
Correct answer: 20 g
Solution
Energy balance m*L_v = (150 - m)*L_f gives m about 20 g of evaporated water.
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