A copper calorimeter of mass 100 g holds 200 g of an ice-water mixture. Steam at 100 deg C (normal pressure) is passed in until the mixture reaches 50 deg C, after which the calorimeter plus contents weighs 330 g. Neglecting heat losses, what was the initial ice-to-water mass ratio? (c_Cu

Question

A copper calorimeter of mass 100 g holds 200 g of an ice-water mixture. Steam at 100 deg C (normal pressure) is passed in until the mixture reaches 50 deg C, after which the calorimeter plus contents weighs 330 g. Neglecting heat losses, what was the initial ice-to-water mass ratio? (c_Cu = 0.42*10³ J/kg/K, c_water = 4.2*10³ J/kg/K, L_fusion = 3.36*10⁵ J/kg, L_condensation = 22.5*10⁵ J/kg)

Accepted Answer

1:1. Balancing the heat given by 30 g of steam against melting the ice and warming the contents gives roughly equal masses of ice and water (about 1:1).

Solution

Related JEE Main Physics questions