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G1, G2, G3 are the conductances of three conductors. When they are connected in series, the equivalent conductance is:

1. 1/(1/G1 + 1/G2 + 1/G3)
2. G1 + G2 + G3
3. G1*G2*G3/(G1 + G2 + G3)
4. given by some other relation

Correct answer: 1/(1/G1 + 1/G2 + 1/G3)

Solution

In series the resistances add (R = 1/G1 + 1/G2 + 1/G3), so the equivalent conductance is the reciprocal of that sum.

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