Exams › JEE Main › Physics
A boy of mass 50 kg sprints at 10 m/s and leaps onto a stationary cart resting on a frictionless floor. After he lands, the cart together with the boy moves at 2.50 m/s. Determine the mass of the cart.
- 150 kg
- 100 kg
- 200 kg
- 120 kg
Correct answer: 150 kg
Solution
Conservation of momentum gives m_boy*u = (m_boy + m_cart)*v, from which the cart mass is 150 kg.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →