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A primary cell has an emf of 1.5 V. When its terminals are short-circuited it delivers a current of 3 A. What is the internal resistance of the cell?
- 0.5 Ohm
- 4.5 Ohm
- 2 Ohm
- 1/4.5 Ohm
Correct answer: 0.5 Ohm
Solution
r = emf / I_short = 1.5 / 3 = 0.5 Ohm.
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