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ExamsJEE MainPhysics

A particle starts moving from time t = 0 and its coordinate is given as x(t) = 4t^3 – 3t. A. The particle returns to its original position (origin) 0.866 units later B. The particle is 1 unit away from origin at its turning point. C. Acceleration of the particle is non-negative. D. The particle is 0.5 units away from origin at its turning point. E. Particle never turns back as acceleration is non-negative. Choose the correct answer from the options given below: (1) A,C,D only (2) A,B,C only (3) C,E only (4) A,C only

  1. A,C,D only
  2. A,B,C only
  3. C,E only
  4. A,C only

Correct answer: A,B,C only

Solution

The correct option includes statements that accurately describe the particle's motion. The particle returns to the origin at a specific time, is 1 unit away from the origin at its turning point, and has non-negative acceleration, indicating it is either speeding up or moving at a constant speed.

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