Exams › JEE Main › Physics

Match List I with List II. List I (Spectral Series for Hydrogen): A. Lyman B. Balmer C. Paschen D. Pfund List II (Spectral Region/Higher Energy State): I. Infrared region II. UV region III. Infrared region IV. Visible region Choose the correct answer from the options given below: (1) A-I, B-III, C-II, D-IV (2) A-II, B-III, C-I, D-IV (3) A-I, B-II, C-III, D-IV (4) A-II, B-IV, C-III, D-I

1. A-I, B-III, C-II, D-IV
2. A-II, B-III, C-I, D-IV
3. A-I, B-II, C-III, D-IV
4. A-II, B-IV, C-III, D-I

Correct answer: A-II, B-IV, C-III, D-I

Solution

The correct matches align the spectral series of hydrogen with their respective energy transitions: Lyman series corresponds to ultraviolet (UV) emissions, Balmer to visible light, Paschen to infrared, and Pfund also to infrared, reflecting the decreasing energy of the emitted photons as the series progresses.

Related JEE Main Physics questions

• An electron in one Bohr orbit with principal quantum number $n=n_1$ can produce 3 distinct spectral lines on de-excitation. In another orbit with principal quantum number $n=n_2$, it can produce 6 distinct spectral lines. What is the ratio of the orbital speeds of the electron in these two orbits?
• An electron in a hydrogen atom is found in an excited state with energy equal to $-3.4$ eV. What is its angular momentum?
• A beam of electrons having energy 12.5 eV is directed at hydrogen gas in the gaseous state at room temperature. The emitted spectrum will contain:
• A hydrogen atom and a $\text{Li}^{2+}$ ion are each in their second excited state. If their electronic angular momenta are denoted by $L_H$ and $L_{Li}$, and their energies by $E_H$ and $E_{Li}$ respectively, which statement is correct?
• For a proton–electron system, the interaction potential is $V = V_0 \ln(r/r_0)$, where $r_0$ is a constant. If Bohr’s model is assumed to hold, how does the radius $r_n$ depend on the principal quantum number $n$?
• In the hydrogen spectrum, the longest wavelength in the ultraviolet region is 122 nm. The shortest wavelength in the infrared region, rounded to the nearest whole number, is

⚔️ Practice JEE Main Physics free + battle 1v1 →