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An EM wave propagating in x-direction has a wavelength of 8 mm. The electric field vibrating y-direction has maximum magnitude of 60 V m^-1. Choose the correct equations for electric field and magnetic field if the EM wave is propagating in vacuum.
- E_y = 60 sin[(π/4)×10^3(x − 3×10^8 t)] j V m^-1 B_z = 2 sin[(π/4)×10^3(x − 3×10^8 t)] k T
- E_y = 60 sin[(π/4)×10^3(x − 3×10^8 t)] j V m^-1 B_z = 2×10^-7 sin[(π/4)×10^3(x − 3×10^8 t)] k T
- E_y = 2×10^-7 sin[(π/4)×10^3(x − 3×10^8 t)] j V m^-1 B_z = 60 sin[(π/4)×10^3(x − 3×10^8 t)] k T
- E_y = 2×10^-7 sin[(π/4)×10^4(x − 4×10^8 t)] j V m^-1 B_z = 60 sin[(π/4)×10^4(x − 4×10^8 t)] k T
Correct answer: E_y = 60 sin[(π/4)×10^3(x − 3×10^8 t)] j V m^-1 B_z = 2×10^-7 sin[(π/4)×10^3(x − 3×10^8 t)] k T
Solution
The correct option accurately represents the electric field with the given maximum magnitude and the appropriate wave number derived from the wavelength, while the magnetic field is calculated using the relationship between the electric and magnetic fields in a vacuum, ensuring the correct amplitude.
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