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ExamsJEE MainPhysics

The electric field in a plane electromagnetic wave is given by \(\vec E = 200\cos\left[\left(\frac{0.5\times10^3}{m}\right)x - \left(1.5\times10^{11}\,\mathrm{rad/s}\right)t\right]\,\frac{V}{m}\,\hat{j}\) If this wave falls normally on a perfectly reflecting surface having an area of 100 cm2. If the radiation pressure exerted by the E.M. wave on the surface during a 10 minute exposure is the value of x. Find the value of x.

  1. x N / 10^2 m^2
  2. x N / 10^3 m^2
  3. x N / 10^4 m^2
  4. x N / 10^5 m^2

Correct answer: x N / 10^5 m^2

Solution

The radiation pressure exerted by an electromagnetic wave on a perfectly reflecting surface is given by the formula P = 2I/c, where I is the intensity of the wave and c is the speed of light. Given the electric field, we can calculate the intensity and subsequently the radiation pressure, which leads to the correct unit of x being N / 10^5 m^2.

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