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Consider an ideal gas confined in an isolated closed chamber. As the gas undergoes an adiabatic expansion, the average time of collision between molecules increases as √q, where V is the volume of the gas. The value of q is (γ = C_p/C_v)
- (γ+1)/2
- (γ−1)/2
- (3γ+5)/6
- (3γ−5)/6
Correct answer: (γ+1)/2
Solution
The correct option is derived from the relationship between the average time of collision and the volume of the gas during adiabatic expansion, where the factor q is related to the specific heat ratio γ. In this context, the expression (γ+1)/2 accurately represents how the average time of collision scales with the volume of the gas.
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