Exams › JEE Main › Physics
Choose the correct relationship between Poisson ratio (σ), bulk modulus (K) and modulus of rigidity (η) of a given solid object
- σ = (6K − 2η)/(3K − 2η)
- σ = (6K + 2η)/(3K − 2η)
- σ = (3K − 2η)/(6K + 2η)
- σ = (3K + 2η)/(6K + 2η)
Correct answer: σ = (3K − 2η)/(6K + 2η)
Solution
The correct option expresses the Poisson ratio in terms of the bulk modulus and modulus of rigidity, reflecting the relationship between these mechanical properties of materials, which is essential for understanding how materials deform under stress.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →