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A wire of length 1 m moving with velocity 8 m/s at right angles to a magnetic field of 2 T. The magnitude of induced emf, between the ends of wire will be ________
- 20V
- 16V
- 8V
- 12V
Correct answer: 16V
Solution
The induced emf in a wire moving through a magnetic field can be calculated using the formula emf = B * L * v, where B is the magnetic field strength, L is the length of the wire, and v is the velocity. Substituting the values (B = 2 T, L = 1 m, v = 8 m/s) gives emf = 2 * 1 * 8 = 16 V.
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