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Glycerin of density 1.25 × 10³ kg m⁻³ is flowing through the conical section of pipe. The area of cross-section of the pipe at its ends are 10 cm² and 5 cm² and pressure drop across its length is 3 N m⁻². The rate of flow of glycerin through the pipe is x × 10⁻⁵ m² s⁻¹. The value of x is _____.
- 4
- 2
- 8
- 1
Correct answer: 4
Solution
The correct option is 4 because applying the principle of conservation of mass (continuity equation) and Bernoulli's equation allows us to calculate the flow rate. Given the pressure drop and the cross-sectional areas, the flow rate can be derived, leading to a value of 4 × 10⁻⁵ m² s⁻¹.
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