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A block of mass 10 kg starts sliding on a surface with an initial velocity of 9.8 m s⁻¹. The coefficient of friction between the surface and block is 0.5. The distance covered by the block before it comes to rest is [use g = 9.8 m s⁻²].

1. 4.9 m
2. 9.8 m
3. 12.5 m
4. 19.6 m

Correct answer: 9.8 m

Solution

The block comes to rest due to the work done against friction, which can be calculated using the initial kinetic energy and the frictional force. The distance covered is determined by equating the initial kinetic energy to the work done by friction, leading to a distance of 9.8 m.

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