Exams › JEE Main › Physics
Water droplets are coming from an open tap at a particular rate. The spacing between a droplet observed at 4th second after its fall to the next droplet is 34.3 m. At what rate the droplets are coming from the tap ? (Take g = 9.8 m/s²)
- 3 drops / 2 seconds
- 2 drops / second
- 1 drop / second
- 1 drop / 7 seconds
Correct answer: 1 drop / second
Solution
The correct option is 1 drop per second because the distance fallen by each droplet after 4 seconds, calculated using the formula for free fall (d = 0.5 * g * t²), matches the observed spacing of 34.3 m, indicating that a new droplet is released every second.
Related JEE Main Physics questions
⚔️ Practice JEE Main Physics free + battle 1v1 →