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A scooter accelerates from rest for time t1 at constant rate a1 and then retards at constant rate a2 for time t2 and comes to rest. The correct value of t1/t2 will be:

1. (a1 + a2)/a2
2. a2/a1
3. a1/a2
4. (a1 + a2)/a1

Correct answer: a2/a1

Solution

The ratio of the times t1 and t2 is determined by the relationship between the acceleration and deceleration rates. Since the scooter accelerates at a1 and then decelerates at a2, the time spent accelerating (t1) is proportional to the acceleration rate, while the time spent decelerating (t2) is proportional to the deceleration rate, leading to the ratio t1/t2 = a2/a1.

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