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A hydraulic press can lift 100 kg when a mass'm' is placed on the smaller piston. It can lift ______ kg when the diameter of the larger piston is increased by 4 times and that of the smaller piston is decreased by 4 times, keeping the same mass 'm' on the smaller piston.
- 1600
- 6400
- 25600
- 102400
Correct answer: 25600
Solution
In a hydraulic press, lifted load = m * (A_large/A_small). Increasing the larger diameter 4x multiplies its area by 16, and decreasing the smaller diameter 4x divides its area by 16, so the ratio grows 256x: 100 * 256 = 25600 kg.
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