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AC voltage V(t) = 20 sinωt of frequency 50 Hz is applied to a parallel plate capacitor. The separation between the plates is 2 mm and the area is 1 m². The amplitude of the oscillating displacement current for the applied AC voltage is ________. [Take ε₀ = 8.85 × 10⁻¹² F/m]
- 21.14 μA
- 83.37 μA
- 27.79 μA
- 55.58 μA
Correct answer: 27.79 μA
Solution
The displacement current in a capacitor is calculated using the formula I_d = ε₀ * A * (dV/dt), where dV/dt is the rate of change of voltage. For the given AC voltage, the maximum displacement current can be derived from the amplitude of the voltage and the capacitor's parameters, leading to the correct answer of 27.79 μA.
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