A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is: (1) 0.0314 N (2) 9.859 × 10⁻² N (3) 6.28 × 10⁻³ N (4) 9.859 × 10⁻⁴

Question

A block of 200 g mass moves with a uniform speed in a horizontal circular groove, with vertical side walls of radius 20 cm. If the block takes 40 s to complete one round, the normal force by the side walls of the groove is: (1) 0.0314 N (2) 9.859 × 10⁻² N (3) 6.28 × 10⁻³ N (4) 9.859 × 10⁻⁴ N

Accepted Answer

9.859 × 10⁻⁴ N. The normal force exerted by the side walls of the groove is determined by the centripetal force required to keep the block moving in a circular path. Given the mass, radius, and time for one complete revolution, the calculation shows that the normal force is 9.859 × 10⁻⁴ N, which corresponds to the necessary centripetal force for the block's motion.

Solution

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